Question

In a right angle∆ABC right angled at c if tanA=1 verify 2SinAcosA=1​

Answer 1

Answer:

By PT.

H = √2

sin = 1/√2

cos = 1/√2

2*1/√2 *1/√2 = 1

2*1/2 = 1

1=1

LHS = RHS

Answer 2

SOLUTION =》

IN ∆ABC GIVEN

TAN A=1

BC/AC=1

BC=X AND AC =X

BY B.P.T

AB^2=AC^2+AB^2

AB^2=X^2+X^2

AB=√2x

sinA=BC/AB=X/√2X=1/√2

AND,COSA=AC/AB=X/√2X=1/√2

2SINACOSA=2×1/√2×1/√2=1

HOPE IT HELP YOU

I KNOW I AM LATE

BUT I AM TRYING TO EXPLAIN EVERY POINT OF SOLUTION