In a right angle triangle ABC,
(a) If AB = 6 cm, BC = 8 cm, Find AC
(b) If AC= 13cm, BC = 5cm, Find AB
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Answers
Answered by
1
According to Pythagoras theorem
AB^2+ BC^2 = AC^2
8^2 +6^2 = AC^2
64+36 = AC^2
AC^2 = 100
AC = √100 = 10
13^2= AB^2+5^2
169 -25 = AB^2
144 = AB^2
AB = √144 = 12
AB^2+ BC^2 = AC^2
8^2 +6^2 = AC^2
64+36 = AC^2
AC^2 = 100
AC = √100 = 10
13^2= AB^2+5^2
169 -25 = AB^2
144 = AB^2
AB = √144 = 12
Answered by
4
hello friend your answer is
Here in 1st
Ab=6
Bc=8
And Ac=10 by pgt
Ac²=Ab²+Bc²
=36+64=100
√100=10
in second
Same like as 1st
Ac²=Ab²+bc²
Ab²=Ac²-Bc²
=13²-5²
144=√144=12
Here in 1st
Ab=6
Bc=8
And Ac=10 by pgt
Ac²=Ab²+Bc²
=36+64=100
√100=10
in second
Same like as 1st
Ac²=Ab²+bc²
Ab²=Ac²-Bc²
=13²-5²
144=√144=12
Happy8888:
hlo
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