In a right angle triangle ABC, angleB=90degree,AB=8cm,AC=10cm,BC=?
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Answered by
4
By Pythagoras theorem, ABsq+BCsq= Acsq
8sq +ACsq=10sq
64+Acsq=100
ACsq=100-64=36
AC = under root 36 i.e. 6.
8sq +ACsq=10sq
64+Acsq=100
ACsq=100-64=36
AC = under root 36 i.e. 6.
Answered by
4
hey dear here is your answer
given that triangle ABC is a right angle triangle at point B
by using phythagorus theorem
(Hy)2 = (b) 2 + (h) 2
hypotenuse AC = 10 CM
base Bc = ?
height AB = 8cm
so
(10)*2 = (Bc)*2 + (8)2
100= Bc*2 +64
Bc*2 = 100-64
Bc *2= 36
so Bc= square root of 36 = 6
So Bc = 6cm
hope helps you
given that triangle ABC is a right angle triangle at point B
by using phythagorus theorem
(Hy)2 = (b) 2 + (h) 2
hypotenuse AC = 10 CM
base Bc = ?
height AB = 8cm
so
(10)*2 = (Bc)*2 + (8)2
100= Bc*2 +64
Bc*2 = 100-64
Bc *2= 36
so Bc= square root of 36 = 6
So Bc = 6cm
hope helps you
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