Question

simplify.............

Answer 1

=  (b-a)(b+a)/2a^2-2ab+3ab-3b^2 =  -(a-b)(a+b)/2a(a-b)+3b(a-b) =  -(a-b)(a+b)/(a-b)(2a+3b) =  -(a+b)/(2a+3b)

Answer 2

Answer:

$\longrightarrow\:\sf{\dfrac{-(b + a)}{2a + 3b}}$

Step-by-step explanation:

$\longrightarrow\:\sf{\dfrac{b^2 - a^2}{2a^2 + ab - 3b^2}}$

$\longrightarrow\:\sf{\dfrac{(b-a) \times (b+a)}{2a^2 + 3ab - 2ab - 3b^2}}$

$\longrightarrow\:\sf{\dfrac{-(a-b) \times (b+a)}{a \times (2a + 3b) - b \times (2a + 3b)}}$

$\longrightarrow\:{\boxed{\sf{\dfrac{-(b + a)}{2a + 3b}}}}$