Question

In a right angle triangle ABC, right angled
at B, AB=6cm, BC=8cm ,then AC=​

Answer 1

Answer:

10cm

Step-by-step explanation:

Given: AB=6cm. BC=8cm Angle B =90 degrees

By Pythagoras theorem

AC'2 = AB'2 + BC'2

So

AC'2 = (6)'2 + (8)'2

= 6*6 + 8*8

=36+64

=100

AC= under root of 100

AC=10 cm

Answer 2

Answer:

AC = 10

Step-by-step explanation:

if triangle is right angled at B , AC is hypotenuse side

$(ab) {}^{2} + (bc) {}^{2} = (ac) {}^{2} \\ 6 {}^{2} + 8 {}^{2} = (ac) {}^{2} \\ (ac) { }^{2} = 100 \\ ac = \sqrt{100} \\ ac = 10$

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