In a right angle triangle ABC ,right angled at B, AB=6cm, BC =8cm then AC =___ *
Answers
Answer:
10cm
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Given
Length of AB = 6cm
Length of BC = 8cm and
Right angled at B
We have to find
The length of side AC
According to Pythagoras theorem Addition of square of side AB and BC will equal to Square of third side AC that is
{(AB)}^{2} + {(BC)}^{2} = {(AC)}^{2}(AB)
2
+(BC)
2
=(AC)
2
On Putting Values
\begin{gathered}= > {8}^{2} + {6}^{2} = {(AC)}^{2} \\ = > 64 + 36 = {(AC)}^{2} \\ = > 100 = {(AC)}^{2}\end{gathered}
=>8
2
+6
2
=(AC)
2
=>64+36=(AC)
2
=>100=(AC)
2
On Removing Square
\begin{gathered}= > AC = \sqrt{100} \\ = > \huge \boxed{AC = 10cm}\end{gathered}
=>AC=
100
=>
AC=10cm
Therefore;
Length of the side AC will be 10cm.
Answer:
AC=root (AB^2+BC^2)
AC=root (36+84)
AC=root (120)
AC=10.9 (approx )
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