Question

In a right-angle triangle ABC, right angled at B, AB=6cm, BC=8cm, then AC=
A. 12

B. 10

C. O 21

D. O 14 h N​

Answer 1

Answer:

ɪɴ ᴀ ʀɪɢʜᴛ ᴀɴɢʟᴇ ᴛʀɪᴀɴɢʟᴇ ᴀʙᴄ, ʀɪɢʜᴛ ᴀɴɢʟᴇᴅ ᴀᴛ ʙ ᴀʙ =ᴄᴍ, ʙᴄ =ᴄᴍ, ᴛʜᴇɴ ᴀᴄ =

ʙʏ ᴘʏᴛʜᴀɢᴏʀᴀs ᴛʜᴇᴏʀᴇᴍ

ʜʏᴘᴏᴛᴇɴᴜsᴇ ²= sɪᴅᴇ²+sɪᴅᴇ²

ʜʏᴘ²= 6²+8²

ʜʏᴘ²=+36+64

ʜʏᴘ²= 100

ʜʏᴘ =10

✔ʙ.

ᴘʟᴇᴀsᴇ ᴍᴀʀᴋ ᴍᴇ ᴀs ʙʀᴀɪɴʟɪᴇsᴛ ᴀɴsᴡᴇʀ... ᴘʟᴇᴀsᴇ

Answer 2

Question :-

• In a right-angled triangle ABC, right angled at B, AB = 6 cm and BC = 8 cm. Find the value of AC.

A) 12 cm.

B) 10 cm.

C) 21 cm.

D) 14 cm.

Answer :-

• AC = 10 cm.

• Option b) is correct.

To find :-

• AC.

Step-by-step explanation :-

• Here, it is given that in a right angled triangle ABC, right angled at B, AB = 6 cm and BC = 8 cm. We have to find the value of AC.

As the right angled triangle is right angled at B, the hypotenuse will be AC while AB and BC will be the legs of the triangle.

Pythagoras theorem states that :-

$\underline{\boxed{\sf Hypotenuse^2 = Perpendicular^2 + Base^2}}$

Substituting the given values in this formula,

$\rm \longrightarrow Hypotenuse^2 = 6^2 + 8^2$

$\rm \longrightarrow Hypotenuse^2 = 36 + 64$

$\rm \longrightarrow Hypotenuse^2 = 100$

$\longrightarrow \rm Hypotenuse = \sqrt{100}$

$\longrightarrow \rm Hypotenuse = 10 \: cm$

Hence :-

• AC = 10 cm.

• Option b) is correct.

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