Math, asked by anjalisinghal6oznibl, 10 months ago

in a right angle triangle ABC right angled at B sin a equal to 3 by 2 find the value of sin square A + cos square C bracket minus 10 Square x cos square a solution​

Answers

Answered by sks2971996
1

It's mentioned in the question that sin a equals 3 by 2 which is sin a=1.5 This is never possible since sin a takes values between -1 and 1. So, there is an error in the question. Please check the question.

Similar questions