in a right angle triangle ABC right angled at B sin a equal to 3 by 2 find the value of sin square A + cos square C bracket minus 10 Square x cos square a solution
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It's mentioned in the question that sin a equals 3 by 2 which is sin a=1.5 This is never possible since sin a takes values between -1 and 1. So, there is an error in the question. Please check the question.
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