in a right angle triangle ABC right angled at p square of the hypotenuse is equal to twice the product of the other two sides show that Sin A is equals to Cos A
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Answer:
∠A=∠C=45°
Step-by-step explanation:
Consider AB=a , BC=b , CA=c ;
Given : c²=2ab ;
Using pythagoras theorem ,
c²=a²+b² ;
Substitue c²,
∴ a²+b² = 2ab;
∴ a²+b²-2ab = 0;
∴ (a-b)² = 0;
∴ a=b;
∴ It is an isosceles right angled triangle.
∴ ∠A = 45° .
∴ As sinA = 1/√2 and cosA=1/√2
∴ Sin A= Cos A .
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