Question

in a right angle triangle ,ABC sin A= cos A then triangle is which type of triangle​

Answer 1

Step-by-step explanation:

In triangle ABC , we see

angle B= 90°

A+C=90

sin(A+C)=sin(A)cos(C)+sin(C)cos(A)

[sin(A)=cos(A)]

=sinA[cosC+sinC]