Three vertices of the parallelogram taken in order are ( -1,0),( 3,1 )and (2,2) respectively. Find the coordinate of the fourth vertex.
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let the fourth vertex be (x,y)
(note: if we use equal side property of parallelogram to find the equations, we will fall in trouble due to quadratic terms. so we will use different property of parallelogram)
The diagonals of a parallelogram bisect deach other
thus mid point of one diagonal is mid point of other diagonal also
now, mid point of diagonal with vertex (x,y) and (3,1)
= (x+3)/2, (y+1)/2
mid point of diagonals with vertex (-1,0) and (2,2)
= (-1 + 2)/2, (0+2)/2
= 1/2, 1
both mid points are same so,
(x+3)/2 = 1/2
x + 3 = 1
x = -2
(y+1)/2 = 1
y + 1 = 2
y = 1
thus, coordinates are (-2, 1)
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