Question

In a right angle triangle ABC , with right angle at A , if AB = 16cm and AC = 63 cm , then the value of sin B + cos B​

Answer 1

Answer:

Ans B=38cm

Step-by-step explanation:

p^2+b^2=h^2

Answer 2

Answer:79/65

Step-by-step explanation:we can find BC by using pythagoras theorem

so AB^2 + AC^2 = BC^2 . 16^2 + 63^2 = BC^2 . We get root of 4225 which is 65. So BC=65 cm. Then  sin B = opposite/hypotenuse=16/65 + cos B = adjacent/hypotenuse=63/65. 16+63/65=79/65.

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