Question

In a right angle triangle ABC with right angle at B, in which a=24 units, b=25 units and
BAC = 0. Then, find cos 0 and tan ,​

Answer 1

Answer:

cos0=1

Step-by-step explanation:

WKT,

cos(a-b) = cosacosb + sinasinb -----(1)

=>cos0=cos(90-90)---------(2)

cos(90-90) = cos90.cos90 + sin90.sin90 (from 1)

=>cos(90-90) = 1.1+0.0=1

From 2,

cos0=1

As BAC = 0 and assuming ΔABC exists,

C=90(ASP)

tanC=tanB=ND or 1/0

tanA = 0 [derived from tan(a-b)]

Contradiction to the fact that lines perpendicular to the same line are parallel hence ΔABC doesn't exist.