In a right angle triangle ABC with right angle at B,in which a= 24 units, b=25 units and angle BAC=teta. Then, find cos teta and tan teta
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Answer:
cos theta= 25/1201
tan theta= 24/25
Step-by-step explanation:
AB (perpendicular)= 24....(given)
BC(base) =25....(given)
According to pythagoras theorem =>
(AB)^2 + (BC)^2= (AC)^2
=> (24×24)+ (25×25)
=>576+625= 1201 ( HYPOTENUSE)
we know
cos theta= base/hypotenuse...
=> 25/1201
tan theta=perpendicular/base
=> 24/25
(you can leave them in fractions no need to simplify)
Hope it helps
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