In a right angle triangle pqr , r=90 degrees , pq=24cm and qr=6 cm and in triangle find p.
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Given In △PAR,∠PAR=90∘
⟹PR2=PA2+AR2
⟹PR=62+82=100=10 cm
In △PQR,
PQ=24 cm,PR=10 cm,QR=26 cm
Here QR2=262=676,PQ2+PR2=242+102=576+100=676
⟹QR2=PR2+PQ2
⟹∠QPR=90∘
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Answer:
In a right angle triangle pqr , r=90 degrees , pq=24cm and qr=6 cm and in triangle find p.
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