Three vectors A of length 3 cm and 30 degree, B of 4 cm and 120 degree and C of 5 cm 90 degree (all make an angle with the x-axis) are there. Prove the associative law (A+B)+C = A+(B+C) BY VECTOR ADDITION.
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Let xˉ=30 units
Bˉ=44 unit
cˉ=5 units
A+B=C′ squaring m both side
(A+B)2=C2=1
A2+B2+2ABcosθ=C2
32+42+2×3×4cosθ=52
24cosθ=25−25
cosθ=0/2
cosθ=0
θ=cos−1(0)=90o
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a2 + 2ab + b2 – c2 = (a2 + 2ab +b2) – c2. = (a + b)2 – (c)2. = (a + b + c) (a + b – c) ...
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