Math, asked by Swarajraaga567, 1 year ago

In a right angle triangle, the hypotenuse is 10cm more than the shortest side. If third side is 6cm less than the hypotenuse, find the sides of the right angle triangle. ​

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Answered by abiramiragu
2

Answer:

Step-by-step explanation:

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abiramiragu

Secondary SchoolMath 5+3 pts

The hypotenuse of a right angled triangle is 6 cm more than twice the shortest side. If the third

side is 2 cm less than the hypotenuse, what are the sides of the triangle in cm?

Report by Oliym 26.01.2018

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abiramiragu

Abiramiragu · Expert

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gaurav2013c

Gaurav2013c Maths AryaBhatta

Let the base be p

Hypotenuse = 2p +6

Perpendicular = 2p + 4

By Pythagoras theoram

(2p+6)^2 = (2p+4)^2 +p^2

=> 4p^2 +36 + 24p = 4p^2 + 16 +16p +p^2

=> 36+ 24p = p^2 + 16p + 16

=> p^2 - 8p - 20 = 0

=> p^2 - 10p +2p - 20 = 0

=> p(p-10) +2(p-10) = 0

=> (p-10)(p+2) = 0

p = 10 and - 2

Length can't be negative

So,

p = 10

Base = 10

Perpendicular = 24

Hypotenuse = 26

Hope it help you

Please mark as brainliest if you liked the solution


Swarajraaga567: I didn't mention any word like (twice) in the question.
Swarajraaga567: Pls check
Answered by mohamed36
2

Hey mate here is your answer

10^2=6^2+c^2

100 =36+c^2

100-36=c^2

64 =c^2

Root of 64 = c

8=c

THERFORE THE SIDES OF TRIANGLE ARE 6,8 and 10.

PLEASE MARK MY ANSWER AS A BRAINLIST..

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