Question

In a right angled ABC, if tan B=12/5
then find sin B.
​

Answer 1

Answer:

sinB=12/13

Step-by-step explanation:

Perpendicular=12

base#=4

hypotuneos = 13

sinB=perpendicular/hypotuneos

=12/13

Answer 2

Answer:

sinB=5/3

Step-by-step explanation:

Since 2 sides of this right angled triangle are 5 and 12,third side is 13 by pythagoras rule a^2+b^2=c^2

Here b was the angle opposite the 12cm side so longest side is hypotenuse or 13cm

There cosB becomes

5/13