in a right angled triangle 2 acute angles are in the ratio of 7:11.find the measure of the acute angles..........if you know accurately alone answer
Answers
Answered by
31
As the sum of angles of a triangle is 180
Then, let the acute angles be 11x and 7x
180=90+11x+7x
180-90=18x
90=18x
90/18 =x
5=x
Then acute angles are:-
7*5=35°
11*5=55°
Then, let the acute angles be 11x and 7x
180=90+11x+7x
180-90=18x
90=18x
90/18 =x
5=x
Then acute angles are:-
7*5=35°
11*5=55°
Answered by
15
Right angled triangle has 1 angle = 90°
And Ratio of angles is given , i.e.,7:11
Let the acute angles be 7x &11x
In a triangle,
Sum of all angles = 180° (Angle Sum Property)
⇒90°+7x + 11x = 180°
18x=90
x= 90/18° = 5
∴Angles = 7x
=7 * 5 =35°
and , 2nd angle,
11*5 = 55°
And Ratio of angles is given , i.e.,7:11
Let the acute angles be 7x &11x
In a triangle,
Sum of all angles = 180° (Angle Sum Property)
⇒90°+7x + 11x = 180°
18x=90
x= 90/18° = 5
∴Angles = 7x
=7 * 5 =35°
and , 2nd angle,
11*5 = 55°
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