Question

In a right angled triangle ABC, angle A = 90 degree and AD is a perpendicular on BC. Prove that angle BAD =angle ACB

Answer 1

Answer:

hi your answer is

Step-by-step explanation:

TO PROVE : LBAD=LDAC (L =ANGLE)

LBAD+LCAD=90° ---------- (1)

LBAD+LCAD=90° -----------(2)

(BY EXTERIOR ANGLE PROPERTY)

ON SOLVING EQUATION (1) AND (2)

LBAD + LDAC=LDAC + LACB (L=ANGLE)

LBAD=LACB

HENCE PROVED

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Answer 2

Therefore Using the Exterior angle property, BAD = ∠BCA is proved.

Given:

ΔABC is a right-angled triangle with ∠A = 90° and AD ⊥ BC.

To Find:

Prove that ∠BAD = ∠ACB.

Solution:

The given question can be solved as shown below.

Given that,

ΔABC is a right-angled triangle with ∠A = 90° and AD ⊥ BC.

Using the Exterior angle property, We can write the following equations.

∠BAD + ∠CAD = 90° ---------- (1)

∠BCA + ∠CAD = 90° -----------(2)

On solving both the equations,

⇒ ∠BAD + ∠CAD = ∠CAD + ∠BCA

⇒ ∠BAD = ∠BCA

Hence, Proved.

Therefore Using the Exterior angle property, BAD = ∠BCA is proved.

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