In a right angled triangle ABC angle
B = 90 IF BC /AB =1/root3 Find AB/AC
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Given,
From trigonometry, we know that they ratio of base to height ( perpendicular ) of a particular angle { A } is known as cotA.
In the question, ratio of base to height is 1 / √3
cot∅ = 1 / √3
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From trigonometric table, 1 / √3 = cot 60°
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cot∅ = tan60°
∅ = 60°
Ratio of height to hypotenuse ( AB : AC ) of a particular angle { A } is known as sinA
AB / AC = sin60°
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From trigonometric table,
sin 60° = √3 / 2
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AB / AC = √3 / 2
From trigonometry, we know that they ratio of base to height ( perpendicular ) of a particular angle { A } is known as cotA.
In the question, ratio of base to height is 1 / √3
cot∅ = 1 / √3
----------------------------
From trigonometric table, 1 / √3 = cot 60°
----------------------------
cot∅ = tan60°
∅ = 60°
Ratio of height to hypotenuse ( AB : AC ) of a particular angle { A } is known as sinA
AB / AC = sin60°
----------------------------
From trigonometric table,
sin 60° = √3 / 2
----------------------------
AB / AC = √3 / 2
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