In a right angled triangle ABC, B=90 than by Phythagoras theorem
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Answered by
2
Answer:
ABC is right angle triangle
Angle B =90°
Pythagoras theorem
=AC²=AB²+ BC²
Answered by
2
Answer:
Step-by-step explanation:
D is the midpoint of BC= AD = CD.
Angle B is a right angled triangle.
Consider ΔABC
AC^2 = AB^2 + BC^2 [Pythagoras theorem]
⇒ AC2 = AB^2 + (2BD)^2 (BC=BD+DC,BD=DC,So we can replace BC by 2BD.
⇒ AC^2 = AB^2 + 4BD^2 ----------- (1)
Consider ΔABC
AD^2 = AB^2 + BD^2 [Pythagoras theorem] ----------- (2)
Subtracting equation (2) from (1), we get
⇒ AC^2 - AD^2 = 3BD^2
⇒ AC^2 - AD^2 = 3CD^2 [ BD = CD,So we can replace BD by CD]
⇒ AC^2 = AD^2 + 3CD^2
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