Question

In a right-angled triangle ABC, D is the foot of the perpendicular from B on the hypotenuse AC. If AB = 3
cm and BC = 4 cm, what is the area of ABD?
0 54 cm?
0 54/29 cm
O 54/23 cm?
O
None of these​

Answer 1

Answer:

by phythogorous theorm,

ac2=ab2+bc2

ac2=9+16

ac=√25

ac=5

given bd is the perpendicular bisector of ac

ad= 5/2

now,

area of triangle abd=1/2× 3×5/2

=15

and answer is none of this