Question

In a right angled triangle ABC, right angled at B, AC = 20 cm and sin C =4/5,find the length of BC.​

Answer 1

BC is 4 cm the cause sin theta is 4 / 5 which means perpendicular upon hypotenuse

Step-by-step explanation:

then then from angle a busy line is 4 cm and ac line is 5 cm

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Answer 2

Answer:

sin c = 4/5= perpendicular/hypotenuse = AB/AC= AB/20

=> AB= 16cm

so now , BC^2= AC^2- AB^2 = (20+16)(20-16) = 36*4

=> BC= 6*2=12cm