In a right angled triangle ABC right angled at B, BC= 15 cm and AB= 8 cm. A circle is inscribed in triangle ABC. Find the radius of a circle.
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AC=root 15^2+8^2
=root 225+64
=root 289
=17cm
let I be the centre of the circle
and D be a Point on BC such that ID perpendicular to BC.
F be a point on AB such that IF perpendicular to AB.
Now, so BDIF is a square.
And BD=BF.
2(a+b+c)=15+17+8
a+b+c=40/2
=20
Therefore, a=3, b=12, c=5
Therefore radius, IF= ID= IE=3CM...
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