Question

In a right angled triangle ABC where AB is perpendicular AC is base and BC is hypotenuse

value given: AB= $\sqrt{x}$
BC= $\sqrt{x+5}$
angle A= 90 degree
Evaluate: sinC.cosC.tanc+cos²C.sinA

HELP

Answer 1

here is a little logic
sinc.cosc.tanc+cos^2c.sina
=sinc.cosc.sinc/cosc+cos^2.sina
=sin^2c+cos^2c.sina
=sin^2c+cos^2c.sin90
=sin^2c+cos^2c(1)
=sin^2c+cos^2c
=1
this is the perfect answer