Question

raman while doing an experiment to find out the percentage of water absorbed by raisins measured the mass of dry raisins as 50g.he soaked the raisins in water for four hours and againmeasured the mass as 80g.calculate the percentage of water absorbed by the raisins.

Answer 1

Weight of dry rasins=50g Wieght of wet rasins=80g Weight of water absorbed=80-50 =30g Percentage of water absorbed=30/50*100 =60%

Answer 2

Mass of dry raisins = 50g

Mass of wet raisins = 80g

Weight of water absorbed by the raisins = 80g - 50g = 30g

Percentage of water absorbed by the raisins = weight of water absorbed * 100 / mass of dry raisins

30g * 100 / 50g = 60%