Math, asked by srinivassamala008, 5 months ago

In a right angled triangle ABC with right angle at B, in which a= 24 units, b =25 units
and BAC =0. Then, find cos 0 and tan 0.

Answers

Answered by Anonymous
34

Answer:

Given that,

in right angle triangle

b=25units,a=24units

angleABC=90, angleBAC=theta

By above we get,

AC=hypotenuse=25units

BC=side opposite to angle theta=24units

By applying Pythagoras theorem we get

AB=side adjacent to angle theta=7units

Now we have,

cos(theta)=side adjacent to angle theta/hypotenuse

cos(theta)=7/25

tan(theta)=side opposite to angle theta/side adjacent to angle theta

tan(theta)=24/7

Hence cos(theta)=7/25

and tan(theta)=24/25

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Answered by praneethpalugup769ly
0

Answer:

That is not possible mate...

Step-by-step explanation:

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