In a right angled triangle ABC with right angle at B, in which a= 24 units, b =25 units
and BAC =0. Then, find cos 0 and tan 0.
Answers
Answered by
34
Answer:
Given that,
in right angle triangle
b=25units,a=24units
angleABC=90, angleBAC=theta
By above we get,
AC=hypotenuse=25units
BC=side opposite to angle theta=24units
By applying Pythagoras theorem we get
AB=side adjacent to angle theta=7units
Now we have,
cos(theta)=side adjacent to angle theta/hypotenuse
cos(theta)=7/25
tan(theta)=side opposite to angle theta/side adjacent to angle theta
tan(theta)=24/7
Hence cos(theta)=7/25
and tan(theta)=24/25
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Answered by
0
Answer:
That is not possible mate...
Step-by-step explanation:
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