In a right angled triangle, one acute angle is double of the other. Find the acute angles.
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Let acute angle = x
And another angle = 2x
A+B+C = 180degree
Thus 90+x+2x = 180
3x = 180-90
3x = 90
X = 90 devide by 30
X = 30
And acute angle = 30
And another one = 60
And another angle = 2x
A+B+C = 180degree
Thus 90+x+2x = 180
3x = 180-90
3x = 90
X = 90 devide by 30
X = 30
And acute angle = 30
And another one = 60
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