Question

In a right angled triangle PQR, right angle at Q. If QR=5cm, PQ=13cm. Determine find cot R-tan P [2]

Answer 1

Step-by-step explanation:

The value of cosec(A+B) = 1

Step-by-step explanation:

In a triangle ABC , right angle at C

i.e °

then,

A+B+C = 180° (angle sum property)'

putting the value of C

A+B+ 90°= 180°

A+B= 180°-90°

A+B= 90°

we have to find the value of cosec(A+B)

putting the value of A+B

cosec (90°)

value of cosec 90°= 1

hence,

the value of cosec(A+B) = 1

#Learn more:

Triangle ABC is a right triangle, right at c then the value of cosec spuare A - tan square B is