In a right angled triangle PQR, right angled at Q, X is the midpoint of PR. prove PQ=XR=QX
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due to mid point x px=XR.
PQX=XQR
QX is common line
∆pQR=∆QXR
XQR=XRQ
XR=QX=PQ
PQX=XQR
QX is common line
∆pQR=∆QXR
XQR=XRQ
XR=QX=PQ
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