Prove that cottheta-tan theta = 2cos2theta-1/ sintheta cos theta
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cotQ-tanQ=2cos2Q-1/sinQ cosQ
LHS=cotQ-tanQ
=cotQ/sinQ -sinQ/cosQ
=cos^2Q-sin^2Q/sinQ cosQ
cos2Q/sinQ cosQ
=2cos2Q-1/sinQ cosQ =RHS
LHS=cotQ-tanQ
=cotQ/sinQ -sinQ/cosQ
=cos^2Q-sin^2Q/sinQ cosQ
cos2Q/sinQ cosQ
=2cos2Q-1/sinQ cosQ =RHS
Answered by
2
helping answer.........................
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