Question

In a right angled triangle Sin 0 =5 /13
. Find all the trigonometric ratios for the triangle.​

Answer 1

Answer:

In this way:

(Without further information about the angle

A

, I assume that that angle is in the first quadrant)

sin

A

=

√

1

−

cos

2

A

=

√

1

−

25

169

=

√

169

−

25

169

=

=

√

144

169

=

12

13

,

and

tan

A

=

sin

A

cos

A

=

12

13

5

13

=

12

13

⋅

13

5

=

12

5

.

Answer 2

Answer:

sin 0 = 5/13

5^2 +x^2=13^2

x^2=13^2-5^2

x^2=169-25

x^2=144

x=12

cos =12/13

tan=5/12

cot=12/5

sec=13/12

cosec=13/5