in a right triangle abc,right-angled at b,bc=12cm and ab=5cm.the radius of the circle inscribed in the inscribed in the triangle(in cm) is
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b=90
bc=12
ab=5
ac²=ab²+bc²
=25+144=169
ac=√169=13 cm
diameter of circle = ab+bc-ac
= (12+5)-13 =4
diameter =4
2r=4
radius=4/2=2 cm
bc=12
ab=5
ac²=ab²+bc²
=25+144=169
ac=√169=13 cm
diameter of circle = ab+bc-ac
= (12+5)-13 =4
diameter =4
2r=4
radius=4/2=2 cm
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