In a right triangle ABC, right angled at C, if tanA=1/√3, find value oF cosA .cosB-sinA. sinB.
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amankhanab111:
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tan A = 1/√3
then AB² = AC² + BC²
= 3+1 = 4
∴ AB = √4 = 2
NOW , COS A . COS B SIN A . SIN B
= √3/2 .1/2 - 1/2 . √3/2 = √3/4 -√3/4 = 0
As angle A = 30 ° and angle B = 60°
then AB² = AC² + BC²
= 3+1 = 4
∴ AB = √4 = 2
NOW , COS A . COS B SIN A . SIN B
= √3/2 .1/2 - 1/2 . √3/2 = √3/4 -√3/4 = 0
As angle A = 30 ° and angle B = 60°
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