Question

In a right triangle ABC, tan(A) = 3/4. Find sin(A) and cos(A).​

Answer 1

Answer:

sin A = 3/5

cos A = 4/5

Hope this will help you

Answer 2

$\large\bf\blue{GIVEN➠}$

tanA=3/4

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$\large\bf\red{To\:Find➛}$

(i).Value of sinA

(ii). Value of cosA

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$\large\bf\purple{SOLUTION➛}$

tanA=$\frac{perpendicular}{base}$=$\bf\frac{3}{4}$

=$\bf\frac{3}{4}$

therefore,

Perpendicular=3

Base=4

Hypotenuse=

$\sqrt{( {3}^{2} + {4}^{2}) }$

Hypotenuse=5

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$\bf\green{(i).Vaue\:of\:sinA:-}$

sinA=$\bf\frac{perpendicular}{hypotenuse}$=$\bf\frac{3}{5}$

$= \frac{3}{5}$

$\bf\green{(ii).Vaue\:of\:cosA:-}$

cosA=$\bf\frac{base}{hypotenuse}$=$\bf\frac{4}{5}$

$\bf\frac{4}{5}$

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$\large\bf\orange{ANSWER➛}$

sinA=$\bf\frac{3}{5}$

cosA=$\bf\frac{4}{5}$