IN A RIGHT TRIANGLE AOB , OA = 3 CM , AB = 6 CM ,,, FIND THE VALUE OF OB ?
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In a right angle triangle:
perpendicular OA =3cm
hypotaneous AB =6 cm
by pythagoras theorem,
perpendicular ^ 2 + base^2=hypotaneous^2
base^2=hypotaneous ^2 - perpendicular ^2
base^2= 6^2 - 3^2
base^2=36-9
base^2=25
base=5
OB=5cm
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