In a right triangle pqr the hypotenuse of length 10 cm angle pqr = 30 degree find the area of triangle
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Hypotenuse is 10 cm.
Let the other two sides a,b
Sin 30= a/10
a=5
Cos 30=b/10
b=(3)^1/2×5
Area=ab=25×(3)^1/2
vivvek:
Its ab/2 sorry
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