in a right triangle the two sides are 15 cm and 8 metre find the hypothesis
Answers
BD 1 AC, and is the radius of the cone formed.
In right- angled AABC, AC? = AB? + BC? - AC? = 152 + 202
- AC? = 225 + 400 AC? = 625
- AC = 25 cm
So, CD = 25 - AD
In right angled AABD
ABP = ADP + BD2
BD2 = 152 - ADP.... (1)
In right - angled ACBD
CB? = BD? + CD?
- BD? = 202 - (25 - AD)....(2)
From (1) and (2)
152 - ADP = 202 - (25 - AD)
+225 - ADP = 300 - 625 + 50AD - ADP
-50AD = - 450
- AD = 9 cm - CD = 25 - 9 = 16 cm
So, BD2 = 152 - AD... (from (1))
BD? = 225 -81- BD = + 12
-
Since BD is the radius, and radius cannot be negative, BD = 12 cm
Volume of the double cone = = Volume of upper cone + Volume of lower cone
+ 3
-글까2(AD+ CD)=글찌(12)7(25)= 1200T cm?
Surface area of the double cone
= Curved Surface area of upper cone + Curved surface area of lower cone
= Tr(AB) + Tr(BA) = Ttr(15 + 20)
= n12(35)= 420T cm²
..
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Answer:
H2=p2+b2
H2=15sq +8sq
H2=225+64
H2= 289
h=√289
h=17 cm