Question

in a right tringl ABC circumscribes a circle of raduis r.If AB and BC ae of length 8 cm and 6cm respectively ,find the value of r.

Answer 1

By Pythagoras theorem
AC square=AB square+BCsquare
Ac square =64+36
Ac=10cm
r=a+b-c/2
r=8+6-10/2
r=14-10/2
r=4/2
r=2cm
So value of r is 2 cm
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Answer 2

Hey!

♣ TRIGONOMETRY ♣

We know,
Pythagoras theorem
i.e (hypotenuse)^2 = (perpendicular)^2 + (base)^2
Here,
(AC)^2 = (AB)^2+(BC)^2
(AC)^2 = 64 + 36
(AC)^2 =100
AC = √100
AC = 10 cm

Now,
r = a + b - c/2
r = 8 + 6 - 10/2
r = 14 - 10/2
r = 4/2
r = 2 cm

Hence r = 2 cm