Question

in a room there is a lamp of 60 watts, 2 tubelights of 40 watts, fan of 80 watt if all of them are used for 10 hours a day then calculate the total electricity consumed in kWh. if one unit of electricity costs rs2.25 calculate the amount in month of may​

Answer 1

$\sf{\large{\underline{\underline{EXPLANATION:}}}}$

Given,

• Power of one lamp=60W

• Power of 2 tubelightes=40×2=80W

• Power of fan=80W

• Time=10hrs/day for 31 days of may month=310hrs

• Total power,P=60+80+80=220W

• Total time,t=310h

Using Formula,

Electricity consumed,

H=pt

→H=(220×310)/1000 kWh

→H=(22×31)/10 kWh

→H=682/10 kWh

→H=68.2 unit (kWh)

Now,,

The cost of one unit electricity=Rs.2.25

Therefore, cost of 68.2 unit electricity

=68.2×2.25

=153.45 Rs.

$\rule{200}2$

❣️❣️❣️★Hope it helps ★❣️❣️❣️