in a sampla of sodiumchloride the percentage of chloride is 45.5 sodium chloride
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Answered by
3
Answer:
The molecular mass of pure sodium chloride (Nacl)=
At mass of Na+At mass of chloride
⇒(23+35.5)
⇒58.5
% of chlorine in pure Nacl=35.5/58.4×100= 60.6
Thus % of purity of Nacl in the sample=45.5/60.6×100⇒75
Answered by
2
Answer:
to prove : molecular mass of sodium chloride
Explanation:
atm of sodium : 23
atm of chloride: 35.5
add all : ( 23. + 35.5)
ans : 58.5
chlorine percentage in sodium chloride is. : 35.5 / 58 . 5 * 100.
Ans : 60.6 percent.
purity percentage of sodium chloride : 45.5 /60.6 * 100.
Ans : 75 precent
therefore the purity of Na Cl is 75 precent and chlorine percentage is 60.6.
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