Question

in a sample of 20 items 2 are defective find the probability of an item selected randomly.​

Answer 1

Answer:

20 mark it as brainlist and follow me

please follow me

Answer 2

Answer:

ANSWER

ANSWERWe have a lot of 6 items, 2 are defective →6−2=4 are non-defective.

ANSWERWe have a lot of 6 items, 2 are defective →6−2=4 are non-defective.P (drawing a defective ite

P (drawing a non-defective item) = 1 - P (drawing a defective item) =1−

P (drawing a non-defective item) = 1 - P (drawing a defective item) =1− Note:4 items can be drawn from a lot of 6 items ways.

ways.Let X be the random variable of drawing 2 defective items from the lot.

ways.Let X be the random variable of drawing 2 defective items from the lot.P(X=0)= P

ways.Let X be the random variable of drawing 2 defective items from the lot.P(X=0)= P P(X=1)= P (one defective item from the lot) = P(one defective, 3 noP(X=2)= P (two defective items from the Therefore the required probability distribu

P(X=xi

P(X=xi )→0 2× 151 +1 2× 158

+1 2× 158 +2 2 × 156

+1 2× 158 +2 2 × 156 = 1532

+1 2× 158 +2 2 × 156 = 1532Variance of X=

+1 2× 158 +2 2 × 156 = 1532Variance of X= 1532

+1 2× 158 +2 2 × 156 = 1532Variance of X= 1532 −( 1520 ) 2 = 4516