Question

In a sample of hard water 0.024 gram per litre of magnesium sulphate and 0.162 gram per litre of calcium hydrogen carbonate ka whole twice is dissolved the hardness of water would be

Answer 1

Answer:

Explanation:

Convert g/lt into moles by dividing by molecular mass

Moles of magnesium sulphate = 0.012

Moles of calcium bicarbonate =0.001

Equivalent of caco3 = equivalent of mgso4

Moles=0.012

Equivalent of caco3 = equivalent of ca(hco3)2

Moles=0.001

Total moles = 0.013

Hardness = weight of caco3/ weight of water ×10^6

=1.3×10^3

=1300 ppm