Math, asked by minion7, 1 day ago

In a school, all pupils play either Hockey or Football or both. 400 play Football,150 play Hockey, and 130 play both games. Find the following a) The number of pupils who play Football only, b) The number of pupils who play Hockey only,The total number of pupils in the school​

Answers

Answered by pkhyatisrinidhi
3

Answer:

please specify your question

Answered by amitnrw
7

Given : In a school, all pupils play either Hockey or Football or both. 400 play Football, 150 play Hockey, and 130 play both games.

To Find :  a) The number of pupils who play Football only,

b) The number of pupils who play Hockey only,

The total number of pupils in the school​

Solution:

In a school, all pupils play either Hockey or Football or both

=> n ( H ∪ F ) = Total students in school

n(H) = 150

n(F) = 400

n ( H ∩ F) = 130

n ( H ∪ F ) =  n(H)  + n(F) - n ( H ∩ F)

=>  n ( H ∪ F ) =   150  + 400 - 130

=>  n ( H ∪ F ) =   420

Total students in school = 420

Football only = n(F) - n ( H ∩ F)

= 400 - 130

= 270

Hockey only = n(H) - n ( H ∩ F)

= 150 - 130

= 20

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