In a school, all pupils play either Hockey or Football or both. 400 play Football,150 play Hockey, and 130 play both games. Find the following a) The number of pupils who play Football only, b) The number of pupils who play Hockey only,The total number of pupils in the school
Answers
Answer:
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Given : In a school, all pupils play either Hockey or Football or both. 400 play Football, 150 play Hockey, and 130 play both games.
To Find : a) The number of pupils who play Football only,
b) The number of pupils who play Hockey only,
The total number of pupils in the school
Solution:
In a school, all pupils play either Hockey or Football or both
=> n ( H ∪ F ) = Total students in school
n(H) = 150
n(F) = 400
n ( H ∩ F) = 130
n ( H ∪ F ) = n(H) + n(F) - n ( H ∩ F)
=> n ( H ∪ F ) = 150 + 400 - 130
=> n ( H ∪ F ) = 420
Total students in school = 420
Football only = n(F) - n ( H ∩ F)
= 400 - 130
= 270
Hockey only = n(H) - n ( H ∩ F)
= 150 - 130
= 20
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