Math, asked by sidvi2113, 2 months ago

In a school assembly, a placard was shown as in the figure given. ABC is quadrant of a circle and a semicircle is drawn with BC as
diameter. Each section of the placard has
depicted virtues like(l) Hard work (11)
Honesty and (III) Punctuality written on it
boldly​

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Answers

Answered by harshavardhan3901086
0

Answer:

Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.Let Y be a subspace of a metric space (X, d). Then ⊆ is open in Y if and only if =∩ for

some open subset G of X.

Step-by-step explanation:

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