in a school the strength of 8th, 9th, 10th std are respectively 48,42,60find the least number of books required to be distributed equally among the students of 8th, 9thand 10th std
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Answer:
1680
Step-by-step explanation:
in a school the strength of 8th, 9th, 10th std are respectively 48,42,60
To find the least number of books required to be distributed equally among the students, we need to find LCM of Number of students in each class
LCM - Lowest Common Multiplier
48 = 2 * 2 * 2 * 2 * 3
42 = 2 * 3 * 7
60 = 2 * 2 * 3 * 5
LCM = 2 * 2 * 2 * 2 * 3 * 5 * 7 = 1680
the least number of books = 1680
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