In a school there are 50 students in 6A. 88% of the students passed a Mathematics test. The same number of boys and girls failed in the exam. If 42% of the total students are girls, how many boys passed the test?
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Total no. of students = 50
No. of students passed = 88% of 50 = 88/100× 50 = 44
No. of students failed = 50-44 =6
Lets no. Of boys failed = x
According to question,
No. Of girls failed = no. Of boys failed = x
x + x = 6
2x = 6
x =3
No. Of boys failed = 3
% of girls = 42%
Therefore, % of boys = 58%
No. Of boys = 58% of 50 = 58/100 × 50 = 29
No. Of boys passed = no. Of boys - no. Of boys passed=29-3 =26
No. of students passed = 88% of 50 = 88/100× 50 = 44
No. of students failed = 50-44 =6
Lets no. Of boys failed = x
According to question,
No. Of girls failed = no. Of boys failed = x
x + x = 6
2x = 6
x =3
No. Of boys failed = 3
% of girls = 42%
Therefore, % of boys = 58%
No. Of boys = 58% of 50 = 58/100 × 50 = 29
No. Of boys passed = no. Of boys - no. Of boys passed=29-3 =26
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