in a school there are 50 students in class 6- A .88℅ of the students passed a mathematics test.the same number of boys and girls failed in the exam. if 42℅ of the total students are girls ,how many boys passed the test?
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88 percentage of 50 is 44 then three girls and three boys are failed 42 percentage of 50 is 22 girls. total students 50 girls 22 then boys are 50-22=28
failed boys =3 then passed are 28-3= 25
failed boys =3 then passed are 28-3= 25
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In a school there are 50 students in class 6- A
88℅ of the students passed a mathematics test
so 16% failed
the same number of boys and girls failed in the exam.
42℅ of the total students are girls
42℅ of the 50 students are girls
so [42/100*50]=21 girls
so 50-21=29 boys
88%0f 50
=44 students passed
we see that 6 failed
the same number of boys and girls failed in the exam.
so 6/2= 3 boys failed
88℅ of the students passed a mathematics test
so 16% failed
the same number of boys and girls failed in the exam.
42℅ of the total students are girls
42℅ of the 50 students are girls
so [42/100*50]=21 girls
so 50-21=29 boys
88%0f 50
=44 students passed
we see that 6 failed
the same number of boys and girls failed in the exam.
so 6/2= 3 boys failed
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