Math, asked by eka0806, 8 months ago

. In a school there are two sections – section A and section B of Class VI. There are 32 students in section A and 36 in section B. Determine the minimum number of books required for their class library so that they can be distributed equally among students of section A or section B.
please answer with full explanation​

Answers

Answered by Anonymous
6

Answer:

It is given that there are 32 students in section A and 36 students in section B.

To determine the minimum number of books required to distribute equally among students of section A and section B, we need to find the LCM of 32 and 36.

To find the LCM, we find the prime factors of 32 and 36 as follows:

Prime factors of 32 are 2. Prime factorization of 32 in exponential form is:

32=2

5

Prime factors of 36 are 2,3. Prime factorization of 36 in exponential form is:

36=2

2

×3

2

Now multiplying the highest exponent prime factors to calculate the LCM of 32 and 36, we have:

LCM(32,36)=2

5

×3

2

=288

Hence, the minimum number of books required to distribute equally among students of section A and section B are 288.

Answered by 06anandmyra
2

Answer:

288 books.

Step-by-step explanation:

It is given that there are 32 students in section A and 36 students in section B.  

To determine the minimum number of books required to distribute equally among students of section A and section B, we need to find the LCM of 32 and 36.

To find the LCM, we find the prime factors of 32 and 36 as follows:

Prime factors of 32 are 2. Prime factorization of 32 in exponential form is:

32=2  

5

 

Prime factors of 36 are 2,3. Prime factorization of 36 in exponential form is:

36=2  

2

×3  

2

 

Now multiplying the highest exponent prime factors to calculate the LCM of 32 and 36, we have:

LCM(32,36)=2  

5

×3  

2

=288

Hence, the minimum number of books required to distribute equally among students of section A and section B are 288.

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